I am working on a project where I need to find the integer value substituted from a character which is either 'K' 'M' or 'B'. I am trying to find the best way for a user to input a string such as "1k" "12k" "100k" and to receive the value back in the appropriate way. Such as a user entering "12k" and I would receive "12000".
I am new to Lua, and I am not that great at string patterns.
if (string.match(text, 'k')) then
print(text)
local test = string.match(text, '%d+')
print(test)
end
local text = "1k"
print(tonumber((text:lower():gsub("[kmb]", {k="e3"}))))
I don't know what factors you use for M and B. What is that supposed to be? Million and billion?
I suggest you use the international standard. kilo (k), mega (M), giga (G) instead.
Then it would look like so:
local text = "1k"
print(tonumber((text:gsub("[mkMG]", {m = "e-3", k="e3", M="e6", G="e9"})))) --and so on
You can match the pattern as something like (%d+)([kmb]) to get the number and the suffix separately. Then just tonumber the first part and map the latter to a factor (using a table, for example) and multiply it with your result.
local factors = { k=1e3, m=1e6, --[and so on]] }
local num, suffix = string.match(text, '(%d+)([kmb])')
local result = tonumber(num) * factors[suffix]