Get index of a list with tuples in which the first element of the tuple matches pattern

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I have a list of tuples:

    countries = [('Netherlands','31'),
                 ('US','1'),
                 ('Brazil','55'),
                 ('Russia','7')]

Now, I want to find the index of the list, based on the first item in the tuple.

I have tried countries.index('Brazil'), I would like the output to be 2. But instead, that returns a ValueError:

ValueError: 'Brazil' is not in list

I am aware that I could convert this list into a pd DataFrame and then search for a pattern match within the first column. However, I suspect there is a faster way to do this.

valueerror tuples indexing python-3.x list
1 Answers

You can use enumerate() to find your index:

Try:

idx = next(i for i, (v, *_) in enumerate(countries) if v == "Brazil")
print(idx)

Prints:

2
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