I have to build a regular exp which will accept all the numbers from 0 to 168 followed by "N" or "S".
I have prepared the following regular exp which is working fine except that it considers 168.11 as valid input.
Regular Exp:
/\b([1-9]|[1-9][0-9]|1[01][0-9]|16[0-8])(\.\d{1,2})?[N,S]?$/
Valid:
168S
11.2
10
140
125N
130S
3S
3.2
168.00S
Invalid:
168.11
168.12S
168.12N
Can anyone suggest what I am missing? Thank you!
You may use this regex with optional matches:
^\s*(?:(?:\d|[1-9]\d|1[0-5]\d|16[0-7])(?:\.\d{1,2})?|168(?:\.0{1,2})?)[NS]?$
RegEx Details:
^\s*: Match 0 or more horizontal spaces at start(?:: Start non-capture group #1
(?:: Start non-capture group #2
\d: A single digit to numbers from 0 to 9|: OR[1-9]\d: Match numbers from 10 to 99|: OR1[0-5]\d: Match numbers from 100 to 159|: OR16[0-7]: Match numbers from 160 to 167): End non-capture group #2(?:\.\d{1,2})?: Match optional decimal point followed by 1 or 2 digits|: OR168: Match 168(?:\.0{1,2})?: Match optional .0 or .00): End non-capture group #1[NS]?: Match optional N or S before end$: EndWhat about:
^ *(?!0|168\.0?[1-9]|169)(?:\d?\d|1[0-6]\d)(?:\.\d?\d)?[SN]?$
See an online demo
^ - Start line anchor. * - 0+ space characters.(?!0|168\.0?[1-9]|169) - Negative lookahead for a leading zero or literally "168." followed by decimal number containing anything other than zero or literally "169".(?: - Open non-capture group:
\d?\d - 1 Or 2 digits.| - Or:1[0-6]\d - A literal "1" followed by numbers 00 upto 69.) - Close non-capture group.(?:\.\d?\d)? - A 2nd non-capture group (optional) for a decimal number (1-2 digits).[SN]? - Optionally match "S" or "N".$ - End line anchor.You can also use
^(?:(?:[0-9]|\d\d|1[0-5]\d|16[0-7])(?:\.\d\d+)?|168(?:\.0+))[NS]?$
with regexr demo
