Is there a way to return multiple responses to 1 get request?
I have a basic flask app where I am trying to make it run another python app and send the terminal logs to the client side. I can return a json value but I can't return any text or the output of the terminal.
Here is the server side:
from flask import Flask, stream_with_context, request, Response
from flask_restful import Api, Resource
from flask_socketio import SocketIO
import intermedia_choose_action_flask
import subprocess
app = Flask(__name__)
api = Api(app)
socketio = SocketIO(app)
class spamblacklistsend(Resource):
def get(self):
imapp = subprocess.Popen(["python3", "/home/tech/scripts/Intermedia_automate/intermedia_choose_action.py", "--addblockeveryone", "--ed", "test@fakeu.com"], bufsize=10, errors='replace')
imapp.app_context().push()
# p = subprocess.Popen(["python3", "/home/tech/scripts/Intermedia_automate/intermedia_choose_action.py", "--addblockeveryone", "--ed", "test@fakeu.com"], bufsize=10, errors='replace')
return imapp.app_context().push()
api.add_resource(spamblacklistsend, "/spamblacklistsend")
if __name__ == "__main__":
app.run(debug=True)
Here is the client side:
from flask import json
import requests
BASE = "http://127.0.0.1:5000/"
response = requests.get(BASE + "spamblacklistsend")
print(imapp.app_context().push())
I know that return stops the function. Is there anyway to return and continue?