How to Process Uploaded Image with Graphql Apollo with SharpJS in NodeJS?

user_11804213 0
Viewed 635

I have a graphql mutation that gets an image from the frontend, and that then is processed and optimized on my server.

But I can't figure out how to pass my image to sharp.

Here is my code:

const Mutation = {
    createImage: async (_, { data }) => {
        const { file } = data
        const image = await file

        console.log(image)

        const sharpImage = sharp(image)
    }
}

I know the code doesn't work and sharp throws an error saying that the input is invalid. So how can I work with createReadStream and to create an instance of sharp?

When I console.log(image), here is what I see:

image {
  filename: 'image.png',
  mimetype: 'image/png',
  encoding: '7bit',
  createReadStream: [Function: createReadStream]
}

Thanks a lot in advance!

sharp apollo-server graphql node.js
1 Answers

So I figured out the solution to my question.

First, I found out that I needed to add scalar Upload to typeDefs.

Then, I need to add a resolver for Upload like this:

const { GraphQLUpload } = require('graphql-upload');

const server = new ApolloServer({
  resolvers: {
    Upload: GraphQLUpload,
  }
})

Then in my resolver, here is what I had to do:

// this is a utility function to promisify the stream and store the image in a buffer, which then is passed to sharp
const streamToString = (stream) => {
    const chunks = [];
    return new Promise((resolve, reject) => {
        stream.on('data', (chunk) => chunks.push(Buffer.from(chunk)));
        stream.on('error', (err) => reject(err));
        stream.on('end', () => resolve(Buffer.concat(chunks)));
    })
}

const Mutation = {
    createImage: async (_, { data }) => {
        const { file } = data
        const { createReadStream } = await file

        const image = await streamToString(createReadStream())

        const sharpImage = sharp(image)
    }
}
user_118042130
Related