Is it possible to dynamically de-structure return?

I understand this is a very dumb question, I am dumb, maybe confused.

Let us say that I have a module foo.js that after doing works returns an object like this bellow,

return {something, anotherThing, yetAnotherThing};

Now, I want to get those in my bar.js and work with, but not with all of them. Maybe sometimes with something and sometimes with anotherThing etc. So, what I do is,

const foo = require('../foo.js')
const { something } = foo()

Then I work with something in my files.

The problem here is, most of the time, I need something or anotherThing on a random basis. Like I do not know which one I will need. Sometimes I need all of them and somethings I need only one or two.

So, is it possible to write a function that dynamically gets the destructed variables and work with them? For example, if I create an array of the things needed from the foo file and pass that array to a function that takes element from the array to get variable from foo.js and work with it? An incorrect code example of what I am saying will be,

const iAmWrong = ( arr) => {
  
    for (let i = 0; i < arr.length; i++) {
        const { arr[i] } = foo();
    }

    arr[i]();
};

There must be a way to achieve this right? Maybe not how I am thinking it is in code but I hope it is not impossible.

Please help.