I have added the hidden field in the form and inserting the data into the database. I have 16 fields on my page and If the user enters any value in the field then I have to change the value from 0 to 1 in the input field.
I tried the below code but it's not working.
$(document).ready(function() {
//Check this link
$(".onchangefield").change(function() {
var val = $(this).closest(".onchangefield").find(".haschange").val(1);
//$(".haschange").val(1);
alert(val);
});
});
<form action="process.php" name="employee" method="post">
<input type="text" name="name" class="onchangefield">
<input type="hidden" name="haschange[name]" class="haschange" value="0" />
<input type="email" name="email" class="onchangefield">
<input type="hidden" name="haschange[email]" class="haschange" value="0" />
<button type="submit" name="save">Save</button>
<button type="submit" name="send_for_approval">Send to approval</button>
</form>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
How to change the value in the foreach.
<?php
$i=1;
$arrayName = array('1','2','3');
foreach ($arrayName as $key => $value) {?>
<input type="file" name="slider[]" class="fileupload onchangefield">
<input type="hidden" name="haschange[slider][<?php echo $i;?>]" class="haschange" value="">
<?php $i++; } ?>