Dart/Flutter: URI/HTTPClient - disable automatic escaping of %

user_15926446 0
Viewed 240

I have a problem with the dart/flutter URI implementation. % is automatically replaced by %25.

i want to access the following URL: http://some.domain/json.php?key=%DF [%DF=ß in ASCII/latin1]

the code:

    final uri = Uri.http('some.domain', 'json.php', {'key': 'ß'});

results in http://some.domain/json.php?key=%C3%9F [ß in UTF-8]

when trying

    final uri = Uri.http('some.domain', 'json.php', {'key': '%DF'});

it results in: http://some.domain/json.php?key=%25DF [% automatically escaped to %25]

when trying explicit encoding:

    final uri = Uri.http('some.domain', 'json.php',
        {'key': Uri.encodeQueryComponent('ß', encoding: latin1)});

it results in: http://some.domain/json.php?key=%25DF [% automatically escaped to %25]

How can I disable the automatic encoding of % to %25?!

any ideas?

dart flutter uri http
2 Answers

The queryParameters parameter of the Uri.http constructor expects an unencoded map of data that it encodes using it's own standard, since you need to use another standard for this case might be better to use the Uri constructor and build your own query string and pass to the query parameter.

Something like this should do the trick:

final uri = Uri(
  scheme: 'http',
  host: 'some.domain',
  path: 'json.php',
  query: 'key=${Uri.encodeQueryComponent('ß', encoding: latin1)}'
);
user_82000930

If you already know the encoded URL, just use Uri.parse:

var uri = Uri.parse('http://some.domain/json.php?key=%DF');

Uri.parse is far simpler and far less error-prone than attempting to use Uri.http/Uri.https directly. Avoid using those, and complain to anyone who instructed you to use them.

user_1797150
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