How to count number of positive values, given as method argument, in one line?

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I have 3 doubles - a, b and c, passed to a method numPos as 3 different arguments. I want to count the number of positive valuse among them, hence the method's return type is int.
I thought about declaring an Array/List and adding the values to it, checking if the value is greater than 0, but I couldn't even do the first part of my idea - declaring a List and passing all the values to it. Here's the code I wrote:

public static int numPos(double a, double b, double c) {
        return List<double> myList = new List<double>(DoubleStream.of(a,b,c).forEach(i -> myList.add(i))).stream().count();
}
java
1 Answers

You can easily use:

return Stream.of(a, b, c).filter(x -> x > 0).count();

Note that count() return long and not int, you need to change the returned type to long.

Important: You really complicate your code, and you have many mistakes that you should to avoid in future.

user_55580720
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