Need help in understanding how to 3d surface plot using plotly

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I am trying to plot a function z= sinx cosy over -pi to pi

This is what I'm hoping to get

Also shown like this

This is the code I have written in an attempt to do the same:

import plotly.graph_objs as go
from scipy.linalg import toeplitz

x=np.linspace(-np.pi,np.pi,30)
z = [(np.sin(i)*np.cos(i)) for i in x]

fig = go.Figure(data=[go.Surface(x=x, y=x, z=toeplitz(z))])
fig.show()

plotly output that I'm getting

I have not been able to understand what 'grid' or '2d array' format I have to convert my z co-ordinate column data into for getting the right graph. Toeplitz was an attempt to do the same, but it seems symmetric unlike the required graph. Please help

plotly surface visualization python
1 Answers

I think I've got it, if you're facing similar issue you can refer/use the code below

import numpy as np
import plotly.graph_objs as go
f = lambda x,y: np.sin(x) * np.cos(y)
x = np.linspace(-np.pi, np.pi, 30)
y = np.linspace(-np.pi, np.pi, 30)
X,Y = np.meshgrid(x,y)
F = f(X,Y)

fig = go.Figure(data=[go.Surface(x=X, y=Y, z=F)])
fig.show()
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