REGEX Python right quotation mark

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At first this is my REGEX until now

(``|,,|")([^"|^'{2}|`{2}|^,{2}]*)(''|``|")

I think that negation in the secound group that I setted isnt working correctly. I seperated all my negations like you can see, I dont know if that can work.

This should for example find this sentence

``Some question is here ,some text here''

but not this one

``Some question is here ,,some text here''

Im already trying to find the solution for hours but im new at Regex and I couldnt find the solution. Thanks in advance for any help.

python regex
1 Answers

You can use

^(``|,,|")((?:(?!"|'{2}|`{2}|,{2}).)*)(''|``|")$

See the regex demo

Details:

  • ^ - start of string/line
  • (``|,,|") - two backticjks, commas or a double quotation mark
  • ((?:(?!"|'{2}|`{2}|,{2}).)*) - any single char other than line break chars, as many as possible, that is not a " and does not start a '', two backticks, or ,, char sequence
  • (''|``|") - '', two backticks, or a "
  • $ - end of string/line.

See a Python demo:

import re
rx = r"""^(``|,,|")((?:(?!"|'{2}|`{2}|,{2}).)*)(''|``|")$"""
texts = ["``Some question is here ,some text here''", "``Some question is here ,,some text here''"]
for text in texts:
    m = re.search(rx, text)
    if m:
        print(f"MATCHED: {text}")
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