suppose I have a numpy ndarray
[[2, -7, 5], [-6, 2, 0] [1, -4, 2], [-2, 6, 8]]
How to get a numpy nd arry with all negative elements replaced by 0:
[[2, 0, 5], [0, 2, 0] [1, 0, 2], [0, 6, 8]]
Thank you for your valuable time.
suppose I have a numpy ndarray
[[2, -7, 5], [-6, 2, 0] [1, -4, 2], [-2, 6, 8]]
How to get a numpy nd arry with all negative elements replaced by 0:
[[2, 0, 5], [0, 2, 0] [1, 0, 2], [0, 6, 8]]
Thank you for your valuable time.
You can use np.clip for this, clipping between zero and infinity:
arr = np.array([[2, -7, 5], [-6, 2, 0], [1, -4, 2], [-2, 6, 8]])
np.clip(arr, a_min = 0, a_max = np.inf)
array([[2., 0., 5.],
[0., 2., 0.],
[1., 0., 2.],
[0., 6., 8.]])
Otherwise, you can use something like this (note this changes the array in place):
arr[arr <= 0] = 0
>>> arr
array([[2, 0, 5],
[0, 2, 0],
[1, 0, 2],
[0, 6, 8]])
You could use np.where() too:
arr = np.array([[2, -7, 5], [-6, 2, 0], [1, -4, 2], [-2, 6, 8]])
result = np.where(arr<0, 0, arr)
Output:
[[2 0 5]
[0 2 0]
[1 0 2]
[0 6 8]]