Regex lookaround start of line

user_310291 0
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I have this regex https://regex101.com/r/wRBBAz/1

(?<=\s|^|\.)[^ \.]+(?=\s*(\())

Testing with input

test1 {...}
test2();

I specified start of line (^) in lookaround so I don't understand why it selects

}
test2

instead of only

test2
javascript regex
1 Answers

The problem is that [^ .] matches any char but a space and a dot, that is, it matches line break chars.

You can use

(?<![^.\s])[^\s.]+(?=\s*(\())

See the regex demo

Details

  • (?<![^.\s]) - a negative lookbehind that matches a location that is either at the start of string or immediately preceded with a dot or whitespace
  • [^\s.]+ - any one or more chars other than whitespace and .
  • (?=\s*(\()) - a positive lookahead making sure there is zero or more whitespces and then a ( (captured into Group 1) immediately to the right of the current location.
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