Regex positive look behind notepad++

user_15515917 0
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I'm trying to use regex to grab the last 3 digits of a string that varies in size. The beginning of the string always leads with name- Examples:

"Name-0000425" "Name-00123" "Name-123"

I want the regex to grab the last 3 digits of this number and replace it with these digits. This is the regex I have tried but it only grabs the first 3 digits.

(?-s)(?<=Name-)(\d{3})

Any help would be appreciated! Thanks!

regex-lookarounds notepad++ regex
2 Answers

You can use

(?<=Name-)\d*(\d{3})

Replace with $1. See the regex demo.

Alternatively, you may also use (Name-)\d*(\d{3}) and replace with $1$2.

Details

  • (?<=Name-) - a positive lookbehind that matches a location immediately preceded with Name-
  • \d* - any zero or more digits
  • (\d{3}) - Group 1 ($1 refers to this value from the replacement pattern): three digits.

NOTES

  • If you only want to remove initial zeros, you can use the (?<=Name-)0+(\d{3}) regex.
  • If there can be anything else before the last three digits on the line, you may use (?<=Name-).*(\d{3}).
  • If there can be anything else before the last three digits that are inside double quotes on a single line, you may use (?<=Name-)[^"\n\r]*(\d{3}).
user_38329700

Shortest regex will be...

Find what: \d{3}"
Replace it with 789"

user_152080510
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