How to click an image with Selenium in Python?

user_11740346 0
Viewed 70

I'm trying to click this button, but the button is actually an image which doesn't have an ID. I've tried using the Xpath by doing

WebDriverWait(driver, 10).until(
    EC.presence_of_element_located((By.XPATH, "/html/body/table/tbody/tr[1]/td/a"))
).click()

but this wasn't able to find the element. Any help would be great! Here's the relevant HTML

<a class="navcontent" href=f5-h-$$/MSL/jsp/openGimPage.jsp?gimEnv=GIM&amp;ep=GIMV" target="blank>
<img onclick="F5_r2u();F5_Event_common(event);try{return(eval(F5_Invoke_eval_event(null,F5_jsBody(function(){parent.trackUserActivity(this,'o','Portlet : Incident Management '+(this.src).split('/images/')[1].split('.')[0]);
<p id="text" style="top: 7px">View</p></a>

Edit: Here is the remainder of the HTML Remainder of HTML

selenium-chromedriver selenium-webdriver selenium python-3.x python
3 Answers

Found the answer. As KunduK pointed out, it was within an iFrame. I had to use the following to select the iFrame, then click the button within.

driver.switch_to.frame(driver.find_element_by_tag_name("iframe"))
driver.find_element_by_css_selector("body > table > tbody > tr:nth-child(1) > td > a")
user_117403460

Try following xpath to identify the element. Use element_to_be_clickable() instead presence_of_element_located()

WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//a[./p[text()='View']]"))).click()
user_108856840

Thank you for your suggestion. I also had this question,and solved by Tyler's way. But I used code below to solved the problem.

driver.switch_to.frame(browser.find_element_by_tag_name("iframe"))    
driver.find_element(by=By.XPATH, value="XPATH")
user_163304760
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