I know this sounds kind of simple but I'm trying to get the count of "countdown" sequences that exists in my array. Example: [1,2,3,2,5,4,3,0] - > 2 ([3,2] and [5,4,3]) I just need a little push, please!
1 Answers
Just iterate through the list every time the countdown breaks you increment the counter
Python, also known as pseudo code:
def count_finder(l):
prev = l[0]
counter = 0
inCount = False
for num in l[1:]:
if num == prev-1: #Checks if the previous was 1 greater than this one
inCount = True # if it is then "inCount" is True
elif num+1 != prev and inCount: #Checks if your exiting a countdown
inCount = False
counter += 1 #Increment Counter
prev = num #Change previous number to current number for next loop
if inCount: counter+=1 #If the loop ends while in a count down increment counter
return counter
print(count_finder([9, 8, 7, 6, 5, 4]))
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