In python, I want to slice strings in a list in such a way that first few characters from that list must be removed/spliced out.
a=['hello', 'things', 'becoming', 'expensive']
How I can remove the first two characters from each string in the list to get the output
['llo', 'ings', 'coming', 'pensive']
a=['hello', 'things', 'becoming', 'expensive']
b = []
for word in a:
b.append(word[2:])
print(b)
Results in:
['llo', 'ings', 'coming', 'pensive']
This piece:
word[2:]
is saying to start at Index 2 and return everything to the right of it. Indexes start at 0, so the first 2 letters are ignored
There are several ways to do it, but the idea behind is the same, treating the string as a sequence of characters and taking from the 3rd one (index 2, as lists start from 0) until the end, using the : range notation.
Iteratively:
for idx, word in enumerate(a):
a[idx] = word[2:]
Comprehension List:
a = [word[2:] for word in a]
Map
a = list(map(lambda word: word[2:], a))
Possibly, there are other ways, but these are the most common.
a =['hello', 'things', 'becoming', 'expensive']
for char in a :
a[a.index(char)] = char[2:]
print(a)
