I'd like to be able to specify default non-type template parameter by calling one of overloaded fuctions (that are template with full specialization). Following code represents the problem: I expecet FieldType2 getDefaultField<FieldType2>() to be printed, but Called getDefaultField() ! is printed.
#include <iostream>
enum class FieldType1 {
Description1,
Description2,
Description3
};
enum class FieldType2 {
Description1,
Description2,
Description3
};
template<class FiledType>
struct FieldDescription {
constexpr static int startPos{0};
constexpr static FieldType fieldType{};
};
struct ConcreteField2 : public FieldDescription<FieldType2> {};
template<class FieldType>
constexpr FieldType getDefaultField() {
return FieldType{};
};
template<>
constexpr FieldType1 getDefaultField<FieldType1>() {
return FieldType1::Description1;
};
template<>
constexpr FieldType2 getDefaultField<FieldType2>() {
return FieldType2::Description3;
};
template<class FieldDescr,
decltype(FieldDescr::fieldType) fieldType = getDefaultField<decltype(FieldDescr::fieldType)>()>
void process() {
if (fieldType == FieldType2::Description3) {
std::cout << "FieldType2 getDefaultField<FieldType2>()" << std::endl;
}
if (fieldType == FieldType2::Description1) {
std::cout << "Called getDefaultField() !" << std::endl;
}
}
int main() {
process<ConcreteField2>();
return 0;
}