how to split any url and get only source?

user_14749338 0
Viewed 150

I want to split https://abcnews.go.com/ this type of URL.

Want to get abcnews

I used:

.split('//')[1]
.split('www.')[1]
.split('.com')[0]
.split('.org')[0]
.split('.edu')[0]
.split('.info')[0]

I get error can not split.

Any idea how to do it?

javascript split regex
2 Answers

This looks safe:

(?:https?:\/\/(?:www\.)?|www\.)([^.\/]+)

See proof.

EXPLANATION

--------------------------------------------------------------------------------
  (?:                      group, but do not capture:
--------------------------------------------------------------------------------
    http                     'http'
--------------------------------------------------------------------------------
    s?                       's' (optional (matching the most amount
                             possible))
--------------------------------------------------------------------------------
    :                        ':'
--------------------------------------------------------------------------------
    \/                       '/'
--------------------------------------------------------------------------------
    \/                       '/'
--------------------------------------------------------------------------------
    (?:                      group, but do not capture (optional
                             (matching the most amount possible)):
--------------------------------------------------------------------------------
      www                      'www'
--------------------------------------------------------------------------------
      \.                       '.'
--------------------------------------------------------------------------------
    )?                       end of grouping
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    www                      'www'
--------------------------------------------------------------------------------
    \.                       '.'
--------------------------------------------------------------------------------
  )                        end of grouping
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    [^.\/]+                  any character except: '.', '\/' (1 or
                             more times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
  )                        end of \1

JavaScript code:

const url = "https://abcnews.go.com/"
const regex = /(?:https?:\/\/(?:www\.)?|www\.)([^.\/]+)/
const match = url.match(regex)
if (match) {
  console.log(match[1])
}

user_113298900

Do you accept Regex's response?

const url='https://abcnews.go.com/';
let subdomain = url.match(/(\w*)\./)[1];

console.log(subdomain)
// subdomain = "abcnews"

With that, you get the word before the first dot.

I think you get an error after: .split('//')[1].split('www.')[1] Because you have no "www", then the length of the array is 1 (array[0] only).

const rgx=/(?:www\.)?(\w*)\./;
const abc='https://abcnews.go.com/';
const www='https://www.google.com/';

console.log(abc.match(rgx)[1]);
// "abcnews"

console.log(www.match(rgx)[1]);
// "google"

user_41165520
Related