I am currently in the process of writing a parser in Haskell. I have the following code.
{-# LANGUAGE LambdaCase #-}
{-# LANGUAGE OverloadedStrings #-}
module Main where
import Data.Text
newtype Parser a = Parser { runParser :: Text -> Either Text (Text, a) }
char1 :: Char -> Parser Char
char1 c = Parser $ \case
(x:xs) | x == c -> Right (xs, x)
_ -> Left "Unexpected character"
It fails to compile with these two errors.
test.hs:12:6: error:
• Couldn't match expected type ‘Text’ with actual type ‘[Char]’
• In the pattern: x : xs
In a case alternative: (x : xs) | x == c -> Right (xs, x)
In the second argument of ‘($)’, namely
‘\case
(x : xs) | x == c -> Right (xs, x)
_ -> Left "Unexpected character"’
|
12 | (x:xs) | x == c -> Right (xs, x)
| ^^^^
test.hs:12:24: error:
• Couldn't match type ‘[Char]’ with ‘Text’
Expected type: Either Text (Text, Char)
Actual type: Either Text ([Char], Char)
• In the expression: Right (xs, x)
In a case alternative: (x : xs) | x == c -> Right (xs, x)
In the second argument of ‘($)’, namely
‘\case
(x : xs) | x == c -> Right (xs, x)
_ -> Left "Unexpected character"’
|
12 | (x:xs) | x == c -> Right (xs, x)
| ^^^^^^^^^^^^^
I can fix the error by replacing the Text data type with String but I would prefer to use the Text data type.
Is there a way to pattern match with the Data.Text type without first explicitly converting it to a string first? Perhaps there is a GHC extension that would allow me to do this?
Thanks in advance.