I have not found a clear answer to this question yet, even though there are multiple similar questions in SO.
I don't fill-in all the details for the code below, as the actual transformations are not important for my questions.
// Adding _corrupt_record to have records that are not valid json
val inputDf = spark.read.schema(someSchema.add("_corrupt_record", StringType)).json(path)
/**
* The following lazy-persists the DF and does not return a new DF. Since
* Spark>=2.3 the queries from raw JSON/CSV files are disallowed when the
* referenced columns only include the internal corrupt record column
* (named _corrupt_record by default). Caching is the workaround.
*/
inputDf.persist
val uncorruptedDf = inputDf.filter($"_corrupt_record".isNull)
val corruptedDf = inputDf.filter($"_corrupt_record".isNotNull)
// Doing a count on both derived DFs - corruptedDf will also be output for further investigation
log.info("Not corrupted records: " + uncorruptedDf.count)
log.info("Corrupted records: " + corruptedDf.count)
corruptedDf.write.json(corruptedOutputPath)
// Not corrupted data will be used for some complicated transformations
val finalDf = uncorruptedDf.grouby(...).agg(...)
log.info("Finally chosen records: " + finalDf.count)
finalDf.write.json(outputPath)
As you can see, I marked the input dataframe inputDf for persistence (see the reason here), but never did a count on it. Then I derived two dataframes, to both of which I did a count.
Question 1: When I do uncorruptedDf.count, what does it do to the parent dataframe inputdf? Does it trigger caching of the whole inputDf, the part of it that corresponds to uncorruptedDf.count, or nothing? RDD Documentation says that:
When you persist an RDD, each node stores any partitions of it that it computes in memory and reuses them in other actions on that dataset (or datasets derived from it).
Question 2: Does it make sense at this point (before the two count) to persist the derived dataframes corruptedDf and uncorruptedDf and unpersist inputDf? Since there are two actions happening on each derived dataframe, I would say yes, but I am not sure. If so.. what is the correct place to unpersist the parent DF below? (A), (B), or (C)?
uncorruptedDf.persist
corruptedDf.persist
// (A) I don't think I should inputDf.unpersist here, since derived DFs are not yet persisted
log.info("Not corrupted records: " + uncorruptedDf.count)
log.info("Corrupted records: " + corruptedDf.count)
// (B) This seems a reasonable place, to free some memory
val finalDf = uncorruptedDf.grouby(...).agg(...)
log.info("Finally chosen records: " + finalDf.count)
finalDf.write.json(outputPath)
// (C) Is there any value from unpersisting here?
Question 3: Same as previous question but for finalDf vs corruptedDf. As can be seen I perform two actions on the finalDf: count and write.
Thanks in advance!