How to delete last character from output in c

user_14371158 0
Viewed 920

Suppose my code is

void main()
{
    for(i=1;i<5;i++)
    { 
        printf("%d, ",i);
    }
}

The output of this program will be

1, 2, 3, 4,

How can I get output like

1, 2, 3, 4

The last , should be omitted.

printf for-loop c loops
3 Answers
#include <stdio.h>

int main(void)
{
    const char *pad = "";
    for (int i = 1; i < 5; i++)
    {
        printf("%s%d", pad, i);
        pad = ", ";
    }
    putchar('\n');
    return 0;
}

You can't "delete" the character once you've printed it. You have to code so that you don't print what isn't actually wanted.

user_151680

Use an if statement. For example

#include <stdio.h>

int main( void )
{
    for ( int i = 1; i < 5; i++ )
    { 
        if ( i != 1 ) printf( ", " );
        printf( "%d", i );
    }

    putchar( '\n' );
}

The program output is

1, 2, 3, 4

Or for outputting a string.

#include <stdio.h>

int main( void )
{
    const char *s = "1234";
    
    for ( const char *p = s; *p; ++p )
    {
        if ( p != s ) printf( ", " );
        putchar( *p );
    }
    
    putchar( '\n' );
}

Again the program output is

1, 2, 3, 4
user_28772410

By using if and else....!!!!

#include <stdio.h>

int main() {
    // Write C code here
    int i;
    for(i=1;i<5;i++){
        if(i==4){
            printf("%d",i);
        }
        else{
        printf("%d, ",i);}
    
    }

return 0;
}
user_150578180
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