I can't solve a problem with standard output laugh, I'm on Unix operating system, so the file-descriptor of STD_IN = 0, STD_OUT = 1, STD_ERR = 2, basically I tried to close the descriptor associated with the standard output, and then overwrite it with that of the file I want to write to, but when I open the file it is empty. CODE:
#include<fcntl.h>
#include<sys/types.h>
#include<sys/stat.h>
#include<unistd.h>
/*special file's descriptor --use it or constants in unistd.h-- */
#define STD_IN 0 /*standard input stream*/
#define STD_OUT 1 /*standard output stream*/
#define STD_ERR 2 /*standard output-error stream*/
int main(unsigned int num_of_args, char** args)
{
if(num_of_args != 3)
{
write(STD_ERR, "Few argouments.\nThe use = ./executable <message> <file>\n", 69);
return -1;
}
int file_des= open(args[2], O_CREAT, 0640);
if(file_des < 0)
{
write(STD_ERR, "Error, we couldn't open file.\n", 31);
return -1;
}
//I close the descriptor associated with STD_OUT
close(STD_OUT);
//I copy the descriptor associated with fil_des on the first available descriptor(so STD_OUT)
dup(file_des);
write(STD_OUT, args[1], sizeof(args[1]));
close(file_des);
return 0;
}
It should be fine, I don't see any errors, but when I open the file I don't find the message written. Because? help me