I have a session log file generated by informatica powercenter, I need to search and print the workflow name with the file name ..I am using the below command, but it is hardcoded .. what could the possible generic command.
grep -e "workflow: \[wfk_load_oltp_stg_data\]" -o -H filename.log
note : here the text "wfk" is common in all the logs file .. any help how I write the regx t pickup the workflow name
Use
grep -Po 'workflow:\s*\[\Kwfk[^][]*(?=])' filename.log
See proof
Explanation
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workflow: 'workflow:'
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\s* whitespace (\n, \r, \t, \f, and " ") (0 or
more times (matching the most amount
possible))
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\[ '['
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\K match reset operator
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wfk 'wfk'
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[^][]* any character except: ']', '[' (0 or more
times (matching the most amount possible))
--------------------------------------------------------------------------------
(?= look ahead to see if there is:
--------------------------------------------------------------------------------
] ']'
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) end of look-ahead