The IntStream.of(1635148106, 544434464, 1936029505, 6647151) creates a stream of 4 elements. Then, for each of those elements, we will do
e -> IntStream.range(0, 4).map(i -> e >> i * 8)
which basically creates 4 elements resulting from the operations
e >> 0
e >> 8
e >> 16
e >> 24
So, the entire operation e -> IntStream.range(0, 4).map(i -> e >> i * 8) on the elements IntStream.of(1635148106, 544434464, 1936029505, 6647151) results in:
1635148106 6387297 24950 97
544434464 2126697 8307 32
1936029505 7562615 29541 115
6647151 25965 101 0
The flatMap(...) part converts the previous operation to an IntStream.
Then in the next operation:
mapToObj(i -> Character.toString((byte) i))
first (byte) i is applied therefore:
1635148106 6387297 24950 97
544434464 2126697 8307 32
1936029505 7562615 29541 115
6647151 25965 101 0
becomes:
74 97 118 97
32 105 115 32
65 119 101 115
111 109 101 0
which if you look at the ASCII table:

corresponds to :
JAVA
<space>is<space>
Awes
ome<null>
The remaining operations:
.mapToObj(i -> Character.toString((byte) i))
.collect(Collectors.joining());
just convert it to a String representation.
For those wondering how from
1635148106 6387297 24950 97
544434464 2126697 8307 32
1936029505 7562615 29541 115
6647151 25965 101 0
you get:
74 97 118 97
32 105 115 32
65 119 101 115
111 109 101 0
First, convert the first elements into binary, and since one byte is 8 bits, extract the last 8 bits of that binary, and convert the same back to decimal. For instance:
1635148106
in binary is
1100001011101100110000101001010
The last 8 bits:
01001010
in decimal is 74.
Or convert into hexadecimal 1635148106 -> 6176614A exact relevant part (the byte) -> 4A and look directly into the ASCII table -> J.