How to get files from URLs in nodeJS, build a zip file and pipe to cloud storage bucket

I want to build a cloud function that receives an object like this one:

{
    "files": [
        {
            "url": "https://myUrl/cat.jpg",
            "name": "cat.jpg"
        },
        {
            "url": "https://anyOtherUrl/mouse.jpg",
            "name": "mouse.jpg"
        },
        {
            "url": "https://myUrl2/dog.jpg",
            "name": "dog.jpg"
        }
    ],
    "referenceId": "cute-images"
}

I would like to get those files, compress them into a zip file (with name = referenceId), save that zip file to a bucket, and finally, send the zip URL back as a response.

My main problem lies with the use of memory and my desire to make correct use of pipes/streams. I would really appreciate good sources of where to find the documentation for this implementation.

This is what I got for now but I don't know if it's any good:

const ZipStream = require("zip-stream");
const fetch = require("node-fetch");
const { Storage } = require("@google-cloud/storage");

exports.zipBuilder = async (req, res) => {

  // Deleted lines of request validation

  let zip = new ZipStream();
  const queue = req.body.files;

  async function addFilesToZip() {
    let elem = queue.shift();
    const response = await fetch(elem.url);
    const stream = await response.buffer();
    zip.entry(stream, { name: elem.name }, (err) => {
      if (err) throw err;
      if (queue.length > 0) addNextFile();
      else zip.finalize();
    });
  }

  await addFilesToZip();

  const storage = new Storage();
  
  const ourBucket = storage.bucket(process.env.DESTINATION_BUCKET);

  zip.pipe(ourBucket); // this fails

  // Get ZIP URL from bucket

  res.send(zipUrl);
};

Edit: This question seems like a lot of questions in one. But since this must work as a single stream, I ask not for exact answers but of ideas on what to study to get a better understanding of the solution.