How to use %d as a decimal integer with %f in the same line?

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I want to design a function to print the first X(where X is an integer) digits after the decimal(from 0 to X) for a floating point number Y. For eg. print_num(12.123456,4) should give:

   12.0000000
   12.1000000 
   12.1200000
   12.1230000
   12.1234000

Here is a program that I tried to write:

#include<stdio.h>
void printplaces(float N,int X)
{
    for(int i =0;i<=X;i++)
    {
        printf("%.%df\n",N,i);
    }
}
void main()
{
    printplaces(23.23423342,5);
}

But it just prints the output as it is:

%df
%df
%df
%df
%df
%df

I want to know how I can use %d as an integer with %f on the same line.

floating-point printf c
1 Answers

You can use a * in place of the precision. Then you can pass it an an int argument:

printf("%.*f\n", i, N);

This doesn't print any trailing zeros, but you can add that as follows:

for (i=0;i<X;i++) {
    printf("%#.*f", i, N);
    if (i<X) printf("%0*d", X-i, 0);
    printf("\n");
}
user_16871190
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