p [1,2,3].map(&:abs)
p [1,2,3].map(:abs)
p [1,2,3].reduce(&:gcd)
p [1,2,3].reduce(:gcd)
Can someone pls explain why line 2 will throw an error, but not line 4.
Ruby Symbols Syntax
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1 Answers
This isn't a general syntactic thing related to Symbol or Symbol#&. It's a special case built into the implementation of Enumerable#reduce.
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