Firestore OR query

user_4992594 0
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Imagine I have a collection in Firestore with objects of the following format:

{
  /* ... */
  ownerId: "id-1",
  memberIds: [
    "id-2",
    "id-3",
    "id-4"
  ]
}

How can I query Firestore for all documents where the string id-1 is present in the ownerId field OR the memberIds field?

I only found AND queries, like so:

return collection('whatever')
  .where('memberIds', 'array-contains', 'id-1')
  .where('ownerId', '==', 'id-1');

But those will only return me the documents where id-1 is included in both the ownerId field and the memberIds array.

I understand that I could perform multiple queries and join the results, but that would make pagination and ordering too much of a hassle to implement.

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1 Answers

It's not possible in Firestore to execute an OR query like the one you describe.

One solution is to denormalize your data (a very common approach in the NoSQL world) and add, to the document, an extra field which "concatenates" the two other fields, as follows:

{
  /* ... */
  ownerId: "id-1",
  memberIds: [
    "id-2",
    "id-3",
    "id-4"
  ],
  ownersAndMemberIds: [
    "id-1", 
    "id-2",
    "id-3",
    "id-4"
  ]
}

Then you can easily query the doc with

return collection('whatever')
  .where('ownersAndMemberIds', 'array-contains', 'id-1');

Of course it requires that you maintain this array aligned with the other fields, but this is not difficult. Either you do it from your front-end when you update one of the two "main" fields, or through a Cloud Function which is triggered on any change to the doc.

user_33718620
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