IntersectionObserver and position: absolute

user_2768271 0
Viewed 1974

IntersectionObserver does not seem to work when the observed element has position: absolute and the root is not the viewport.

Am I missing something here?

(Try removing the position: absolute to see the expected result.)

let intersectionRoot = document.getElementById("intersectionRoot");
let observedElement = document.getElementById("observedElement");
let shifted = false; // Internal for the example

let interSectionObserver = new IntersectionObserver(
    (entries, observer) => {
        console.log(entries[0].isIntersecting)
    },
    { root: intersectionRoot }
);
interSectionObserver.observe(observedElement);

window.setInterval(
    () => {
        observedElement.classList.toggle("shifted")
    },
    1000
)
#intersectionRoot {
    background-color: red;
    width: 100px;
    height: 100px;
}

#observedElement {
    position: absolute;
    background-color: green;
    width: 50px;
    height: 50px;
}

.shifted {
    transform: translate3d(110px, 0, 0)
}
<div id="intersectionRoot">
    <div id="observedElement" draggable="true"></div>
</div>

intersection-observer css-position javascript
1 Answers

The solution is to add position: relative to the root element. Here's an updated demo.

If you don't explicitly set position: relative to the root element its children (in this case observedElement) refers to the body. From the IntersectionObserver docs: An IntersectionObserver with a non-null root is referred to as an explicit root observer, and it can observe any target Element that is a descendant of the root in the containing block chain.

user_37895270
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