How to properly set a function that returns the difference in years in python?

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I am trying to program a function that returns me the difference in years given an specific date format, which is: "01/%m/%Y":

Here's the code I am using:

import datetime as datetime

###################### function to return difference in years ####################

def years_between(start_year, end_year):
    start_year = datetime.strptime(start_year, "01/%m/%Y")
    end_year = datetime.strptime(end_year, "01/%m/%Y")
    return abs((end_year - start_year).years)

When tested it returns:

years_between("01/10/1900", "01/10/2000")

AttributeError: 'datetime.timedelta' object has no attribute 'years'

Expected function output would be an integer, in the above case would be 100

Is there any other way to correct this function?

date datetime function python
1 Answers

from datetime import datetime

def years_between(start_year, end_year):
    start_year = datetime.strptime(start_year, "%d/%m/%Y")
    end_year = datetime.strptime(end_year, "%d/%m/%Y")
    return abs(end_year.year - start_year.year)


print(years_between("01/10/1901", "01/10/2000"))
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