Seems simple but I can't figure it out. What is the simplest way in Julia to create a new array of type Int8, containing ten 3's ? Thx. J
Obviously
Int8[3,3,3,3,3,3,3,3,3,3]
works but I want to produce much larger arrays.
1 Answers
@mcabbott's suggestion
fill(Int8(3), 10)
was my first thought and the best choice IMHO, but you can also do one of these if your preference goes to any of them
[Int8(3) for _ in 1:10]
or
Int8.(3 * ones(10))
or
Int8(3) * ones(Int8, 10)
[EDIT] or (Oscar Smith suggestion)
Int8(3) .+ zeros(Int8, 10)
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