REGEX expression: get the two letters after the slash or after the last dot

user_888139 0
Viewed 83

I want to pick up the ISO code (two letters) of a country using a REGEX expression

For example, for the country Ireland the ISO code is ie. The ISO code could be found after the slash / or after the last .

This is my RewriteRule:

RewriteRule ^gallery/country(?:/[^/]*([a-zA-Z-9]{2}))?/?$ gallery/gallery.php?country=$1 [L,QSA]

Here are some valid url's... If available, I want to pick the ISO Code:

gallery/country

gallery/country/

gallery/country/ie

gallery/country/ie/

gallery/country/ireland

gallery/country/ireland/

gallery/country/ireland-love.ie

gallery/country/ireland-love.ie/

gallery/country/ireland.69-love.ie/

I've try to adapt the template formula that I use pretty much for all of my seo url's, but i'm having difficulties with this one. Here's what I've done so far.

^gallery/country(?:/[^/]*([a-zA-Z-9]{2}))?/?$

https://regex101.com/r/88azeh/6

.htaccess mod-rewrite regex
2 Answers

Could you please try following, based on your shown samples. Catching everything after . in a reference group and using it while rewriting here. Please make sure you clear your browser cache before testing any URLs.

RewriteEngine ON
RewriteCond %{QUERY_STRING} ^$
RewriteRule \.([a-zA-Z]+){2}/?$ gallery/gallery.php?country=$1 [L]

Above will not check about URI's condition, to make it more specific to gallery only try following.

RewriteEngine ON
RewriteCond %{QUERY_STRING} ^$
RewriteRule ^gallery/country.*\.([a-zA-Z]+){2}/?$ gallery/gallery.php?country=$1 [L]
user_58665800

You can use

^gallery/country/(?:.*[/.])?([a-zA-Z]{2})/?$

See the regex demo. Details:

  • ^ - start of input
  • gallery/country/ - a literal string
  • (?:.*[/.])? - an optional pattern matching
    • .* - any zero or more chars other than line break chars as many as possible
    • [/.] - a / or .
  • ([a-zA-Z]{2}) - Group 1: two ASCII letters
  • /? - an optional /
  • $ - end of string.
user_38329700
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