assume I have a 3-element array like this:
A = [1, 2, 3]
How can I convert it to:
B = [1; 2; 3]
in Julia?
1 Answers
transpose creates an Adjoint object that actually holds a view
julia> A = [1, 2, 3];
julia> A'
1×3 LinearAlgebra.Adjoint{Int64,Array{Int64,1}}:
1 2 3
Wrapping it with collect would make an actual horizontal vector:
julia> collect(A')
1×3 Array{Int64,2}:
99 2 3
You need to however understand that in Julia 1-dimensional Vectors are always vertical while a vector can be also represented by a two-dimensional matrix where one dimension is equal to one:
julia> B=[1 2 3]
1×3 Array{Int64,2}:
1 2 3
julia> C = collect(B')
3×1 Array{Int64,2}:
1
2
3
Finally, each of those can be converted to a standar vector using the vec function or [:] operator:
julia> A == B[:] == C[:] == vec(B) == vec(C) == @view(C[:]) == @view(B[:])
true
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