sed remove first pattern and the last pattern from a string

user_12335153 0
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I'm processing some file names here. I need to remove the ^0 from the end of every file in a specific directory. For example:

root/etc/data.1.2.3^0
root/etc/file.4.5.6^0
root/etc/fileA.7.8.9^0

I want to remove the root/etc/part and the weird ^0 part. So far I figured the following: sed -e 's:root/etc/::' to remove the root/etc/part. Now I'm confused about how to remove the ^0 part.

I tried:sed -e 's:root/etc/^0$::' and sed -e 's:root/etc/\^0$::', but none of them is working.

I think I did not parse ^ as a character in sed correctly since ^ means something else in sed.

sed special-characters regex
3 Answers

You can use

for f in *^0; do 
  mv "$f" $(sed -e 's:root/etc/\(.*\)\^0$:\1:' <<< "$f");
done

See the sed online demo:

s='root/etc/data.1.2.3^0
root/etc/file.4.5.6^0
root/etc/fileA.7.8.9^0'
sed 's:root/etc/\(.*\)\^0$:\1:' <<< "$s"

Output:

data.1.2.3
file.4.5.6
fileA.7.8.9

The pattern matches:

  • root/etc/ - a literal root/etc/ substring
  • \(.*\) - Group 1 (\1 placeholder refers to this value): any zero or more chars
  • \^ - a ^ char
  • 0 - a 0 char
  • $ - end of string.
user_38329700

I tried:sed -e 's:root/etc/^0$::' and sed -e 's:root/etc/\^0$::', but none of them is working.

No, of course those wouldn't work. Both patterns match the string root/etc/^0 appearing at the end of the line.

I think I did not pares ^ as a character in sed correctly since ^ means something else in sed...

That's not the issue. The ^ is special only at the beginning of the pattern or the beginning of a subexpression (to anchor it to the beginning of the input line) and as the first character of character class (to negate the class). Anywhere else it is an ordinary character.

There are various ways you could approach the problem. One would be to use a capturing group in the pattern and a back-reference in the replacement, as demonstrated in your other answer. Another would be simply to perform two s commands per line:

sed -e 's,^root/etc/,,; s,\^0$,,'

The commands must be separated by a newline or semicolon. Note that you do need to escape the ^ at the beginning of the pattern in the second s command, as shown, for it to be interpreted as an ordinary character instead of an anchor.

user_24022720

Use grep like so:

grep -Po '.*/\K[^^]+' list_of_files

For example:

echo 'root/etc/data.1.2.3^0' | grep -Po '.*/\K[^^]+'
# data.1.2.3

Here, grep uses the following options:
-P : Use Perl regexes.
-o : Print the matches only, 1 match/line, not the entire lines.

\K : Pretend that the match starts at this position. That is, ignore the preceding part of the regex when printing the match.
[^^]+ Any characters that are not literal caret (^), repeated one or more times.

SEE ALSO:
grep manual

user_9676210
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