I'm trying to understand what happens when you have both props and useState in one component.
I wrote little example of it which has one parent component that prints its numbers with another child component -
const MyNumbers = (props) => {
const [numbers, setNumbers] = useState([...props.arr]);
function changeNumbers() {
setNumbers((nums) => [...nums.map(() => Math.floor(Math.random() * 10))]);
}
return (
<div className="MyNumbers">
<div>
<button onClick={changeNumbers}>Chane numbers</button>
</div>
<div>
{numbers.map((num, idx) => (
<SingleNumber key={idx} num={num}></SingleNumber>
))}
</div>
</div>
);
};
const SingleNumber = (props) => {
const [num] = useState(props.num);
useEffect(() => {
console.log("useEffect called");
});
return <h3>The number is {num}</h3>;
};
The SingleNumber component uses useState and as you can see clicking on the "Change numbers" action doesn't change the values in the children component.
But when I wrote almost the same code but now SingleNumber doesn't use useState then clicking on the "Change numbers" changes all the values in the children component (like in this demo).
Is it correct to say that a function component with a useState renders once and then only changed if the state changed but not if the props changed ?
