Python recursive function to check if all numbers in a list are even

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This is a question I have to do for a homework assignment. I understand most of it, and the function pretty much works except on one input and I don't know how to fix it.

Here is the code:

def alleven(nums):
    if len(nums) == 0:
        return True
    else:
        if nums[0] % 2 > 0:
            return False
        else:
            return True
            return alleven(nums[1:])

And then:

>>> alleven([0, 1, 0])
True

I think it's the 1 number that is not processing right, but I'm not entirely sure why?

recursion python
1 Answers
def is_even(counter:int=0, even:int=0, values:list=None):
    if counter == len(values):
        if even == counter:
            return "List is even"
        else:
            return "List is uneven"
    
    if values[counter] % 2 == 0:
        even += 1

    counter += 1
    
    return is_even(counter, even, values)

answer = is_even(values=[0, 1, 0])

print(answer)
user_103025280
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