Can someone help me figure out the canonical "tidyeval" way to solve this:
outer()takes a data framedataand an optional(!) tidy selection argumentvar.varis passed on toinner()inner()only performsselect()ifvaris not missing- Requirement: the signature of
inner()andouter()should be the same, since inner() might be called independently
Here's my approach, but it isn't working.
Problem: missing(var) returns TRUE in outer() but FALSE in inner().
inner <- function(data, var) {
print(missing(var))
if (missing(var)) data else dplyr::select(data, {{ var }})
}
outer <- function(data, var) {
print(missing(var))
inner(data, !!rlang::enquo(var))
}
outer(mtcars)
#> [1] TRUE
#> [1] FALSE
#> data frame with 0 columns and 6 rows
inner(mtcars)
#> [1] TRUE
#> mpg cyl disp hp drat wt qsec vs am gear carb
#> Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
#> Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
#> Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
#> Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
#> Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
#> Valiant 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
...
My naive solution would be to check missing(var) in outer and change the call to inner() accordingly (see below), but I wonder if there is a way to just pass on the var argument without any such checks?
# works as desired
outer <- function(data, var) {
print(missing(var))
if (missing(var)) inner(data) else inner(data, !!rlang::enquo(var))
}