Splot triangles from binary data file

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I have a binary files that have binary format='%float32%float32%float32', having D3 points (using 1:2:3). Originally logically points grouped by 3 to form triangles. I want to plot just legs of triangles as a lines using with lines. In ASCII data file I can make so-called datablocks by adding an empty line between triples of lines, but in binary I can't. I want to break a chain of lines at every three points to form at least V-like parts of triangle contours.

Is there an option to make gnuplot to treat a triples of points as separate datablocks?

Is there another option to splot the data as (maybe) a solid triangles?

gnuplot binary-data
1 Answers

I'm still not sure whether I'm fully on the right track. The following code writes your binary data into a table and makes groups of 3 datapoints for a triangle, inserting an empty line and then shifted by one for the next triangle. So, So from the points p1=f1,f2,f3; p2=f4,f5,f6; p3=f7,f8,f9; ... it creates the triangles p1p2p3p1 p2p3p4p2 p3p4p5p3 (space=empty line).

Certainly, not very (memory) efficient, but maybe this gets closer to your final goal. Check help pm3d and help hidden3d, where you might get some additional information. I very much hope that there is a better approach.

Code: (assuming the binary file 'myBinary.bin', not sure whether I decoded your ASCII string correctly)

# plot binary data
reset session

# put binary data into a datablock
set table $Data
    plot 'myBinary.bin' u 1:2:3 binary format='%float32%float32%float32' skip=12 w table
unset table

# separate each triangle by an empty line
set print $Data2
    do for [i=1:|$Data|-2] {
        print $Data[i]
        print $Data[i+1]
        print $Data[i+2]
        print $Data[i]
        print ""          # insert empty line
    }
set print
set pm3d hidden3d
set view 40, 24

splot $Data2 u 1:2:3 w pm3d notitle
### end of code

Result:

enter image description here

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