I have a vector like a. I would like to generate a list b from a. I only typed the first 4 components of the list. Any suggestions of quick ways to achieve this be appreciated:
a <- seq(from =0, to = 359, by = 8)
b <- list(c(0:7), c(8:(8+7)), c(16:(16+7)), c(24:(24+7)))
> b
[[1]]
[1] 0 1 2 3 4 5 6 7
[[2]]
[1] 8 9 10 11 12 13 14 15
[[3]]
[1] 16 17 18 19 20 21 22 23
[[4]]
[1] 24 25 26 27 28 29 30 31
You can create a sequence from min value of a to max and then use findInterval or cut to split the sequence based on intervals.
tmp <- seq(min(a), max(a))
split(tmp, findInterval(tmp, a))
#$`1`
#[1] 0 1 2 3 4 5 6 7
#$`2`
#[1] 8 9 10 11 12 13 14 15
#$`3`
#[1] 16 17 18 19 20 21 22 23
#$`4`
#[1] 24 25 26 27 28 29 30 31
#$`5`
#[1] 32 33 34 35 36 37 38 39
#...
Another way using Map :
Map(seq, a[-length(a)], a[-1] - 1)
This will achieve the desired result
list1 <- list()
for (i in 1:45) {
base=i*8-8
list1[[i]] <- base + 1:8
}