Regex, get all hyperlinks

user_12143126 0
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I try to figure out how to get 2 matches from String Bla bla bla [https://google.com|Google] bla bla bla [https://youtube.com|Youtube]

I want to get 2 matches: [https://google.com|Google], [https://youtube.com|Youtube]. My regex looks likee this: \[.*\|.*\] and with it I get only one match: [https://google.com|Google] bla bla bla [https://youtube.com|Youtube] so it is wrong answer. How to get the right answer?

P.S. google and youtube - the hardcoded example. I get array of data with 1000+ entries, so I need a universal solution.

regex java
2 Answers

You can use

\[([^\]\[|]*)\|([^\]\[]*)]

See the regex demo. Details:

  • \[ - a [ char
  • ([^\]\[|]*) - Group 1: any zero or more chars other than [, ] and |
  • \| - a | char
  • ([^\]\[]*) - Group 2: any zero or more chars other than [ and ]
  • ] - a ] char.

In Java, use

String regex = "\\[([^\\]\\[|]*)\\|([^\\]\\[]*)]";

See the Java demo:

String s = "Bla bla bla [https://google.com|Google] bla bla bla [https://youtube.com|Youtube]";
String regex = "\\[([^\\]\\[|]*)\\|([^\\]\\[]*)]";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(s);
while (matcher.find()){
    System.out.println("Match: " + matcher.group(0));
    System.out.println("Group 1: " + matcher.group(1));
    System.out.println("Group 2: " + matcher.group(2));
}

Output:

Match: [https://google.com|Google]
Group 1: https://google.com
Group 2: Google
Match: [https://youtube.com|Youtube]
Group 1: https://youtube.com
Group 2: Youtube
user_38329700

u need to make quantifier * lazy by adding ? mark , here is an example :

String  s = "Bla bla bla [https://google.com|Google] bla bla bla [https://youtube.com|Youtube]";
Pattern p = Pattern.compile("\\[.*?\\]");
Matcher matcher = p.matcher(s);

while(matcher.find()){
    System.out.println(matcher.group());
}

OUTPUT :

[https://google.com|Google]
[https://youtube.com|Youtube]
user_129678940
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