type Name = String
type Age = age
data Person = P Name Age derieving (eq)
type People = [Person]
smiths = [P "John" 21, P "Willy" 26]
How to get Johns age? Is there any function like (smiths!!0).age? Or is it only possible with pattern matching?
type Name = String
type Age = age
data Person = P Name Age derieving (eq)
type People = [Person]
smiths = [P "John" 21, P "Willy" 26]
How to get Johns age? Is there any function like (smiths!!0).age? Or is it only possible with pattern matching?
You can perform pattern matching:
(\(P _ a) -> a) (smiths !! 0)
But it might be better to define Person with record syntax:
data Person = P {
name :: Name
, age :: Age
} deriving Eq
Then Haskell will automatically construct a "getter" age :: Person -> Age, and then you can access this with:
age (smiths !! 0)