Best way to close the program pressing Esc anytime the user wants?

user_14521601 0
Viewed 252

Which is the best way to close a program anytime by pressing Esc? I need to implement this thing in an important code, but my experiments didn't work.

This is the last one:

from multiprocessing import Process
import keyboard
import sys


def stop_anytime():
    bool = True
    while bool:
        try:
            if keyboard.is_pressed('Esc'):
                sys.exit()
                bool = False
        except:
            break

def print_numbers():
    for n in range(150000):
        print(n)
 

if __name__ == '__main__':
    p1 = Process(target=stop_anytime)
    p2 = Process(target=print_numbers)
    p1.start()
    p2.start()
python-keyboard process multiprocessing python
2 Answers

edit: this works:

import keyboard
import sys

def print_numbers():
    for n in range(150000):
        print(n)
        if keyboard.is_pressed('Esc'):
            sys.exit()


if __name__ == '__main__':
    print_numbers()

you have to join the processes like this:

p1.join()
p2.join()

or maybe that has to be done with threading only

also you maybe could do this:

def print_numbers():
    for n in range(150000):
        print(n)
        if keyboard.is_pressed('Esc'):
            sys.exit()

or possibly even use pygame module for the code above to register key presses

user_145310620

The keyboard module is multithreaded, so you don't need to use the multiprocessing module yourself to do this. I think the cleanest way to do things would be to use the keyboard.hook() function to specify a callback function that does what's needed.

Note: Since this callback will be invoked from a separate keyboard thread, calling sys.exit() in it will only exit that, not the whole program/process. To accomplish that you need to call os._exit() instead.

import keyboard
import os


def exit_on_key(keyname):
    """ Create callback function that exits current process when the key with
        the given name is pressed.
    """
    def callback(event):
        if event.name == keyname:
            os._exit(1)
    return callback


def print_numbers():
    for n in range(150000):
        print(n)


if __name__ == '__main__':

    keyboard.hook(exit_on_key('esc'))
    print_numbers()
user_3552300
Related