C++ multiple access specifiers and order of initialization

We know that in the following code

class Foo1 {
private:
    int i;
    bool b;
public:
    Foo1() : i(7), b(false) {} 
};

"i" is going to be init before "b". If I try to init "b" before "i", I'll get a warning.

what about this case:

class Foo2 {
private:
    int i;
private:
    bool b;
public:
    // what happens if b is first because compiler reordered?
    Foo2() : b(false),  i(7) {} 
};

?

We know that the compiler is free to order "i" and "b" since they are in separate access specifiers.

So what is the order of initialization in this case?

anything guaranteed like in the previous simple case?