I guess dynamically created variable has to be initialized separately and not at the time of allocating. Why the below line of code does not compile? Why do I get the error message " expected ')' before 'p'".
*(int *p = malloc(sizeof(int))) = 23;
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2 Answers
The definition int *p cannot appear inside an expression, it is a syntax error. You must use a definition and a separate expression to initialize the contents:
int *p = malloc(sizeof(int));
*p = 23;
or
int *p;
*(p = malloc(sizeof(int))) = 23;
Note that both of the above forms have undefined behavior in case of memory allocation failure.
This
int *p = malloc(sizeof(int))
is a declaration of the variable p.
You may not use declarations like an expression.
So you need to split this line
*(int *p = malloc(sizeof(int))) = 23;
in two lines like
int *p = malloc(sizeof(int));
and
*p = 23;
Another way is at first to declare the variable p
int *p;
and then to use the declared variable in the expression
*( p = malloc( sizeof( int ) ) ) = 23;
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