Per the pandas docs, iloc provides:
Purely integer-location based indexing for selection by position.
Therefore, as shown in the simplistic examples below, [row, col] indexing is not possible without using loc or iloc, as a KeyError will be thrown.
Example:
# Build a simple, sample DataFrame.
df = pd.DataFrame({'a': [1, 2, 3, 4]})
# No iloc
>>> df[0, 0]
KeyError: (0, 0)
# With iloc:
>>> df.iloc[0, 0]
1
The same logic holds true when using loc and a column name.
What is the difference and when does the indexing work without iloc?
The short answer:
Use loc and/or iloc when indexing rows and columns. If indexing on row or column, you can get away without it, and is referred to as 'slicing'.
However, I see in your example [start:end][[1]] has been used. It is generaly considered bad practice to have back-to-back square brackets in pandas, (e.g.: [][]), and generally an indication that a different (more efficient) approach should be taken - in this case, using iloc.
The longer answer:
Adapting your [start:end] slicing example (shown below), indexing works without iloc when indexing (slicing) on row only. The following example does not use iloc and will return rows 0 through 3.
df[0:3]
Output:
a
0 1
1 2
2 3
Note the difference in [0:3] and [0, 3]. The former (slicing) uses a colon and will return rows or indexes 0 through 3. Whereas the latter uses a comma, and is a [row, col] indexer, which requires the use of iloc.
Aside:
The two methods can be combined as show here, and will return rows 0 through 3, for column index 0. Whereas this is not possible without the use of iloc.
df.iloc[0:3, 0]