Is there a way to use the type of an object as the argument of a type parameter?

user_658077 0
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I'm trying to use shapeless to do additions and removals from Hlists. But I can't seem to get it to work.

So I here are my lists:

object ShapelessExample {

    import shapeless._

    def main(args: Array[String]): Unit = {

        case class Container[T <: Singleton](name: T)

        val a = Container("A") :: Container("B") :: Container("C") :: HNil
        val b = Container("B") :: Container("C") :: HNil

        println {
            a.removeAll[b.type] //doesn't work
        }
    }
}

So the removeAll method on Hlist only takes a type parameter, but I can't seem to use b.type. I can manually specify a.removeAll[Container["B"] :: Container["C"] :: HNil], but is there any way to just use b's type?

scala-2.13 shapeless scala generics
1 Answers

Shapeless tries to remove precisely type b.type but can't find it among Container["A"] :: Container["B"] :: Container["C"] :: HNil so @user is correct, singleton type b.type is too specific.

In order to infer an HList type from a val singleton type try to modify the method

implicit class RemoveAllOps[L <: HList](a: L) {
  def removeAll[L1 <: HList](b: L1)(implicit
    ra: shapeless.ops.hlist.RemoveAll[L, L1]
  ): ra.Out = ra(a)
}

a.removeAll(b) // (Container(B) :: Container(C) :: HNil,Container(A) :: HNil)

or

implicit class RemoveAllOps[L <: HList](a: L) {
  def removeAllFrom[O <: Singleton] = new {
    def apply[L1 >: O <: HList]()(implicit
      ra: shapeless.ops.hlist.RemoveAll[L, L1]
    ): ra.Out = ra(a)
  }
}

a.removeAllFrom[b.type]() //(Container(B) :: Container(C) :: HNil,Container(A) :: HNil)
user_52496210
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