Why cloned struct value still equals to the original struct

user_13042925 0
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I created the following interface:

type cloneable interface {
    clone() cloneable
}

And a person struct (implements cloneable):

type person struct {
    firstName string
    lastName  string
    age       int
}

func (p person) clone() person {
    return person{p.firstName, p.lastName, p.age}
}

Now I attempt to clone my person value like so:

p1 := person{"name", "last", 22}
p2 := p1.clone()

fmt.Println(p2 == p1) // PRINTS 'true', why?

The clone method works as intended, but why p2 equals to p1? these are both values, not references, how can they be equal?

go pass-by-value reference
2 Answers

Two structs will be equal if first, all their field types are comparable and all the corresponding field values are equal.

if your struct has at least one function or one uncomparable value, then you can not compare two structs

user_34159840
user_80306510
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