Suppose I have a two lists:
a = [1,2,3,4,5]
b = [float]
My requirement is to just get the value of the 'a' list in 'b', i.e.
b = [1,2,3,4,5, float]
So, if we either append of insert, that will again create list of list, which I don't want.
Any suggestions
Assume your input is:
a = [1,2,3,4,5]
b = ['float']
b{:] = a+b
print (b)
The output of this will be:
[1, 2, 3, 4, 5, 'float']
If your input is:
a = [1,2,3,4,5]
b = [float]
then your output will be:
[1, 2, 3, 4, 5, <class 'float'>]
this may be a bit clumsy, but it does what you want:
a = [1, 2, 3, 4, 5]
b = ["float"]
print(id(b))
for n in reversed(a):
b.insert(0, n)
print(b) # [1, 2, 3, 4, 5, 'float']
print(id(b))
note that the id does not change - no new list is created.
slice-assignment would also work:
b0 = b[0]
b[:len(a)] = a
b.append(b0)
if you don't mind working with a deque instead of a list you could also do this:
from collections import deque
a = [1, 2, 3, 4, 5]
b = deque(["float"])
b.extendleft(reversed(a)) # deque([1, 2, 3, 4, 5, 'float'])