getting the error code of a sub-command using $(...)

user_2074831 0
Viewed 99

In this code :

echo hello > hello.txt
read X <<< $(grep hello hello.txt)
echo $?

$? refers to the exit code of the read statement which is 0. Is there a way to know if the grep failed (e.g., if hello.txt has been deleted by another process) without splitting the read and grep in two statements (i.e., first grep then check $? then read).

exit-code bash
2 Answers

Use process substitution instead of command substitution + here string:

read X < <(grep 'hello' hello.txt)

This will get you 1 when using echo $?.

PS: If grep fails it will write an error on your terminal.

If you want to suppress error then use:

read X < <(grep 'hello' hello.txt 2>/dev/null)
user_5482250

Just:

X=$(grep hello hello.txt)
echo $?

For general case where you want to use read to do word splitting, then use a temporary variable:

tmp=$(grep hello hello.txt)
echo $?
IFS=' ' read -r name something somethingelse <<<"$tmp"
user_90727530
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